Finding values in an Array

2014 1 30
3 个回答
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更新时间：2014 1 30
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0 个投票

If I have an array such as
Subject= [126;156;1992, 203, 186] % First two digits determine group, additional numbers are specific subject within that group.
Is there a method to only read the first two values of each row in order to determine what group the subject is?
Group= [12;15;19;20;18] %%%This is what I would like the result to be.

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Jos (10584)
Jos (10584) 2014-1-30

1 个投票

Apply some arithmetic:
Subject = [126 156 1992 203 186 10 100 100000]
Group = fix(Subject ./ (10.^floor(log10(Subject)-1)))

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Walter Roberson
Walter Roberson 2014-1-30

0 个投票

Group = floor(Subject ./ 10);

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Aldo Amaya
Aldo Amaya 2014-1-30
Thanks for the reply, the only issue is that they are not all the same number of elements. Subjects elements range from 3-5 currently.

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Aldo Amaya
Aldo Amaya 2014-1-30
编辑：Aldo Amaya 2014-1-30

0 个投票

This was my solution but I wish there was a cleaner way to do it
Group = floor(Namex2 ./ 10);
i=1;
while i<=length(Group)
if Group(i)>=100
Group(i)=floor(Group(i)./ 10);
else
end
i=i+1;
end

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