how to apply dwt and inverse dwt for an image
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hi all..im writing a code for getting an image and perform dwt for one level to get 4 sub bands and apply inverse dwt to reconstruct the image. The LL band should contain the intensity imformation of the image but for me the figure for LL is plain white and when tried for reconstructing image iam getting same white screen image. i am not sure what was the mistake i have done.. the code i have written is shown below,
clear all;
close all;
i=imread('image22.jpg');
sX=size(i);
[LL,LH,HL,HH]=dwt2(i,'db1');
figure(1)
subplot(2,2,1);imshow(LL);title('LL band of image');
subplot(2,2,2);imshow(LH);title('LH band of image');
subplot(2,2,3);imshow(HL);title('HL band of image');
subplot(2,2,4);imshow(HH);title('HH band of image');
X = idwt2(LL,LH,HL,HH,'db1',sX);
figure(2)
imshow(X);
kindly help me to fix the same.
6 个评论
mariena aloor
2019-4-10
Hai Sir
I want to take the features from blood smear image.So how i will use discrete wavelet transform for feature extraction.
I want the code for second level dwt only for the LL band.Kindly give me the matlab code for feature extraction using discrete wavelet transform my mail id is : aloormariena@gmail.com
Walter Roberson
2019-4-10
采纳的回答
Nawin K Sharma
2017-9-25
编辑:Nawin K Sharma
2017-9-25
dwt2 results are in double (Integer) format. For double format, imshow treats non zero values as White and Zero values as Black. That's why you are getting full white screen.
Try this modification in your code
LL=uint8(LL);
uint8 converts double to unsigned integer of 8 bit format,which is used in gray scale or colored images.
If you want o retain double format, use this
imshow(uint8(LL))
7 个评论
lavanya valli
2020-3-10
sir plz send me the 2 level DWT for grey scale image .......vallilavanya04@gmail.com
更多回答(9 个)
chaitanya goteti
2015-9-8
Use uint8 while displaying the bands, like imshow(uint8(LL)). Hope this helps
Wayne King
2014-2-6
编辑:Wayne King
2014-2-6
Are you sure it is just not the scaling of the image in imshow() that is causing you problems?
For example, note:
load woman;
sX = size(X);
[LL,LH,HL,HH]=dwt2(X,'db1');
Xrec = idwt2(LL,LH,HL,HH,'db1',sX);
max(max(abs(X-Xrec)))
The above shows perfect reconstruction. The maximum absolute value of the difference between elements in the original matrix and the reconstructed matrix is on the order of 10^{-13}
4 个评论
shaghayegh alijanian
2015-7-23
i get this error would you please help me? Error using - Integers can only be combined with integers of the same class, or scalar doubles.
Error in jpg4 (line 9) max(max(abs(X) - abs(Xrec)))
Karbala'a Unvi. Science
2014-5-3
Hi every one,... I worked on your code and I did some modification on it and I made it work because I have the same project on my PHD project so if you want the modified code I can send it to you when you send me your e-mail. and give me your opinion. yours Zeyad
3 个评论
Madhu Oruganti
2020-5-26
Dear sir, I am also working for my phD course can you please share the code at oruganti.madhu@gmail.com
Ahmad Shaheen
2016-12-17
After i=imread('image22.jpg'); insert the following: i=im2double(i); and it will works.
0 个评论
Harmeet Kaur
2018-1-2
编辑:Harmeet Kaur
2018-1-2
hello everyone the above code is not giving the reconstructed image. the output of reconstruction is as follows:
4 个评论
Walter Roberson
2018-5-2
The line
max(max(abs(i-Xrec)));
tries to calculate something abut then it throws away the results of the calculation. The easiest repair is to comment out the line.
Karbala'a Unvi. Science
2020-1-29
Dear Sir,
Try this code and tell me is it working ornot..
clc, close all;
clear all;
X=imread('3.bmp');
imshow(X);
X= double(X);
i=imresize(X,[512 512]);
figure(1);
imshow(i);
sX=size(X);
[LL,LH,HL,HH]= dwt2(X,'db1');
figure(2)
subplot(2,2,1);imshow(LL);title('LL band of image');
subplot(2,2,2);imshow(LH);title('LH band of image');
subplot(2,2,3);imshow(HL);title('HL band of image');
subplot(2,2,4);imshow(HH);title('HH band of image');
%%
Xrec=idwt2(LL,LH,HL,HH,'db1',sX);
% sx=size(X)
% A1=idwt2(LL,[],[],[],'db1',sX);
% H1=idwt2([],LH,[],[],'db1',sX);
% V1=idwt2(LL,[],HL,[],'db1',sX);
% D1=idwt2(LL,[],[],HH,'db1',sX);
max(max(abs(X-Xrec)))
figure(3);
imshow(uint8(Xrec));
Ankita Bansal
2018-6-1
编辑:Ankita Bansal
2018-6-1
Hi Fatima, in your code the sizes of X and i are not equal and you are using X as an input to dwt function. Hence whatever calculation will be done after [LL, LH, HL, HH] = dwt2(X,'db1'); will use X. So, when you try to calculate inverse dwt, the data you will get will be of same size as that of X. Also, the datatype of output of idwt is double whereas i is of uint8 datatype. So, the first reason of getting error is different data type and the second reason is size. To check whether the output you are getting is correct or not you can write max(max(abs(X-uint8(Xrec)))) instead of max(max(abs(i-Xrec))).
if true
% code
end
close all;
clear all;
X=imread('image.png');
imshow(X);
i=imresize(X,[512 512]);
figure;
imshow(i);
sX=size(X);
[LL,LH,HL,HH]= dwt2(X,'db1');
Figure;
subplot(2,2,1);imshow(LL);title('LL band of image');
subplot(2,2,2);imshow(LH);title('LH band of image');
subplot(2,2,3);imshow(HL);title('HL band of image');
subplot(2,2,4);imshow(HH);title('HH band of image');
Xrec=idwt2(LL,LH,HL,HH,'db1',sX);
max(max(abs(X-uint8(Xrec))));
figure;
imshow(Xrec);
Hope this helps
5 个评论
Rahul Kumar Singh
2018-10-4
hello, i am currently working on image steganography in transform domain. As i am new to this i only the theoritical part . my question is after getting the subbands LL,LH,HL,HH how do we obtain the wavelet coeffients so that we can divide them into blocks of four and then choose m\2 blocks out of it(where m is the length of the secret message(in bits) to be embedded ) so that 2 bits can be embedded in each block by pattern matrix method.
i hope you understood my question. any suggestion will help.
Karbala'a Unvi. Science
2020-1-29
try this one
clc, close all;
clear all;
X=imread('3.bmp');
imshow(X);
X= double(X);
i=imresize(X,[512 512]);
figure(1);
imshow(i);
sX=size(X);
[LL,LH,HL,HH]= dwt2(X,'db1');
figure(2)
subplot(2,2,1);imshow(LL);title('LL band of image');
subplot(2,2,2);imshow(LH);title('LH band of image');
subplot(2,2,3);imshow(HL);title('HL band of image');
subplot(2,2,4);imshow(HH);title('HH band of image');
%%
Xrec=idwt2(LL,LH,HL,HH,'db1',sX);
% sx=size(X)
% A1=idwt2(LL,[],[],[],'db1',sX);
% H1=idwt2([],LH,[],[],'db1',sX);
% V1=idwt2(LL,[],HL,[],'db1',sX);
% D1=idwt2(LL,[],[],HH,'db1',sX);
max(max(abs(X-Xrec)))
figure(3);
imshow(uint8(Xrec));
pallavi singh
2020-8-11
SIr,
Can u tell me the code of dwt ?
4 个评论
Walter Roberson
2020-8-12
You have a small number of choices:
- You can apply dwt for every row (of every color plane) independently;
- You can apply dwt for every column (of every color plane) independently;
- You can apply dwt for every row (of every color plane) independently, and transpose the result and apply dwt to every row (of every color plane) of the result. This is similar to the way that fft2() is fft(fft(IMAGE).')
- You can apply dwt for every column (of every color plane) independently, and transpose the result and apply dwt to every column (of every color plane) of the result. This is similar to the way that fft2() is fft(fft(IMAGE).'). In theory this should give the same result as #3
- You can reshape the image into a single continuous row and apply dwt to that
- You can reshape the image into a single continuous column and apply dwt to that
To be clear: dwt can only be used on one vector at a time, so you cannot just apply it to a 2D or 3D (RGB) array.
See also: dwt2()
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