how to divide the image into overlapping blocks?

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sehreen
sehreen 2014-2-11
评论： Walter Roberson 2017-9-18
i need to identify the duplicate regions in an image for that i have to divide the image into overlapping blocks of fixed size lets suppose 16*16 pixels and then dct is performed on each block.
Division of blocks should be performed in such a way that if the block is a square of size b × b then the square is slid by one pixel along the image from the upper left corner right and down to the lower right corner.so please tell me how can i perform such kind of division of an image.

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采纳的回答

Walter Roberson
Walter Roberson 2014-2-11
See mat2cell() to divide the array into cells. Start by letting the CurrentImage be the original image. Then repeat
T = CurrentImage;
%throw away partial blocks
T(end-mod(size(T,1),16)+1:end, :) = [];
T(:, end-mod(size(T,2),16)+1:end) = [];
now break out of loop if T is empty
Now you can mat2cell to extract 16 x 16 blocks. Store them. Then,
CurrentImage = CurrentImage(2:end,2:end);
and start loop over again. You would be extracting the blocks one over and one down from the first set of blocks. Next iteration you would be going with one over and one down from that, and so on.
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sehreen
sehreen 2014-2-13
编辑：sehreen 2014-2-13
thank u very much for your respose
[row col]=size(img);
for i=1:row-7
for j=1:col-7
BLOCK=img(i:i+7,j:j+7)
end
end
sir i am using the above code to divide the image into overlapping blocks of size 8*8 . Now i need to perform
  1. DCT on each block
  2. Quantize the DCT coefficients of each block and then store each quantized block in a row of a matrix.can you please tell me how could i perform it.

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更多回答（1 个）

Anand
Anand 2014-2-11
You could use the blockproc function. You would need to specify a 'BorderSize' of [1 1] and use a BlockSize of [16 16].
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TUSHAR MURATKAR
TUSHAR MURATKAR 2017-9-18
@image analyst, i tried in the way you explained but i got empty matrix.

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