How can I read a complex number vector?

Hi, I have this problem. I'm trying to read a complex number vector from a txt file using this structure:
fid=fopen ('VarName4.txt','r');
acorrente=fscanf(fid,'%f');
fclose (fid);
VarName4.txt is a vector 1000x1 like this:
[0.0141451080390089-0.00224036502008852i
0.0141451080390089-0.00224036502008852i
0.0141451080390089-0.00224036502008852i
0.0141451080390089-0.00224036502008852i...]
Using the structure before, the answer is:
acorrente =
0.0141
-0.0022
Why it doesn't work? Could someone teach me? Thanks a lot!

2 个评论

It doesn't work because you are telling fscanf to expect a floating point number. Fscanf won't read in imaginary numbers.
Hi José-Luis. So, How can I do? thanks.

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 采纳的回答

André Luiz, this should do:
fid = fopen ('VarName4.txt','r');
ii = 1;
while ~feof(fid)
acorrente(ii, :) = str2num(fgets(fid));
ii = ii + 1;
end
fclose(fid);
...read each line of the text file, convert it from string to number and save it in the matrix. The loop will keep reading until the end of the file ( feof ) is reached.

3 个评论

When using %f you are reading using fixed-point notation, which cuts off the number after some digits. E.g., try,
A = 0.014145108039009 - 0.002240365020089i;
sprintf('%f', A)
ans =
0.014145
Hi Mischa Kim. Thank you for your attention. It worked! But the numbers are still being cut. Could you help again? Thanks.
original: 0.0141451080390089-0.00224036502008852i answer: 0.0141 - 0.0022i I need a complete number. Thanks a lot.
That's a formatting setting, the number is saved correctly. In the MATLAB command window put
format long

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