if else doesn't go through the loop

Nur
2014 2 13
3 个回答
回答已采纳
更新时间：2014 2 13
2 次查看（30 天）

0 个投票

Hi,
I have a problem with if else and loop. Lets say I have an array zz double.The value of zz is 2,10,11,23,26,30,37,38,48,53,63,65,66,70,79 and 80. For each element will have its own calculation in the if else statement. I've tried to do if else like this
for Z = 1:numel(zz)
if zz==1;
% if true,do calculation 1
elseif zz==2;
% if true,do calculation 2
and so on.
When I run,it should output result for calculation 2 because the first element in the array is equal to 2. But the coding seems doesn't go through the if else coding. Any help is really appreciated. Thanks.

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 采纳的回答

Roger Stafford
Roger Stafford 2014-2-13
编辑：Roger Stafford 2014-2-13

1 个投票

You have forgotten to index your zz entries in the for-loop. It should read:
for Z = 1:numel(zz)
if zz(Z)==1;
% if true,do calculation 1
elseif zz(Z)==2;
% if true,do calculation 2
Otherwise you are placing an impossible condition on each 'if' or 'elseif'. None of them could ever be true.

更多回答（2 个）

Image Analyst
Image Analyst 2014-2-13

1 个投票

How did you arrive at those numbers? Are you sure they're integers? Did you hard code them in, or are they supposed to be integers because of operations, like 2 = 1.3 + 0.7? If so, that 2 won't equal a int32(2). Read the FAQ: http://matlab.wikia.com/wiki/FAQ#Why_is_0.3_-_0.2_-_0.1_.28or_similar.29_not_equal_to_zero.3F
Nur
Nur 2014-2-13

0 个投票

The numbers are come from my previous coding, as shown below
ActualVelocity=[ActualVelocityP1,ActualVelocityP2..ActualVelocityP82]
zz = find(ActualVelocity>50.000);
Those zz numbers I got from above command.zz will have the ActualVelocity which are >50.00.So number 2,10,11,23,26,30,37,38,48,53,63,65,66,70,79 and 80 represent the location of the value(>50) in the zz array.

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