How to do segmentation for detecting microaneurysms?

2 次查看(过去 30 天)
hi, please help me. i want to create a program for the detection of microaneuryms in diabetic retinopathy diseases. i have retinal image and success doing vascular segmentation. the point is, i've been using a region growing from http://www.mathworks.com/matlabcentral/fileexchange/32532-region-growing-2d3d-grayscale but it just give me one object of microaneurysm like this
i want the result like this
this is my original image after using adaptive histogram
what should i do? or is there a recommended method that i can use?

回答(2 个)

Nitin
Nitin 2014-2-16
Hope this gets you started:
I=imread('retinal.PNG'); I2 = rgb2gray(I); I_bin = I2>150;
In the next step, you can choose the smaller regions you are interested in using bwselect and or regionsprops based on your criteria

Image Analyst
Image Analyst 2014-2-16
编辑:Image Analyst 2021-9-3
People have done this before and published their methods. Look for them in section 20.5 here:
Most likely, you'll find robust algorithms won't be just a hundred or two hundred lines long, as I don't expect that it's a simple problem.
A quick and dirty, non-robust method would be something like this
  1. threshold image
  2. find areas and perimeters
  3. remove largest region (the main vessel network)
  4. compare circularities (Perimeter^2/(4*pi*area)) of remaining regions and keep regions with low circularity values to keep compact blobs rather than stick-like blobs.
  2 个评论
Mustapha Seidu
Mustapha Seidu 2021-9-3
Hi, this is the second time I am coming across this link today. Can you provided an updated link pls? This particular one has nothing relating to the problem. Thank you.
Image Analyst
Image Analyst 2021-9-3
Where was the first one, if you still remember. Obviously the link worked once but I guess they changed it from
http://iris.usc.edu/Vision-Notes/bibliography/contentsmedical.html#Medical%20Applications,%20CAT,%20MRI,%20Ultrasound,%20Heart%20Models,%20Brain%20Models
to the new link:
I'll change it in my original answer also.

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