having trouble with for loops

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Joseph
Joseph 2014-2-13
回答： Alonso Mukendi Kalonji 2022-10-29
Having Trouble...
'Sum of N^2 with N = 1 to 1,000 using a for loop'

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采纳的回答

Andrei Bobrov
Andrei Bobrov 2014-2-13
out = 1;
for ii = 2:1000
out = out + ii^2;
end
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Thomas
Thomas 2014-2-13
what answer do u expect?

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更多回答（2 个）

Roger Stafford
Roger Stafford 2014-2-13
Here's a way to check your answer:
n = 1000;
s = n*(n+1)*(2*n+1)/6;
This gives you the same value as
s = sum((1:n).^2);
Alonso Mukendi Kalonji
a = 1;
n= 1000;
for i = 1: n
a = a+i^2
end
disp(a)

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