having trouble with for loops

2014 2 13
3 个回答
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更新时间：2022 10 29
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Andrei Bobrov
Andrei Bobrov 2014-2-13

0 个投票

out = 1;
for ii = 2:1000
out = out + ii^2;
end

3 个评论
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Joseph
Joseph 2014-2-13
SumN=0; % initializes N^2
for N=1:1000
SumN = SumN + N^2;
end
Still not giving me correct answer...Don't know what I'm doing wrong
Thomas
Thomas 2014-2-13
what answer do u expect?
Joseph
Joseph 2014-2-13
i got it thanks

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更多回答（2 个）

Roger Stafford
Roger Stafford 2014-2-13

0 个投票

Here's a way to check your answer:
n = 1000;
s = n*(n+1)*(2*n+1)/6;
This gives you the same value as
s = sum((1:n).^2);

0 个投票

a = 1;
n= 1000;
for i = 1: n
a = a+i^2
end
disp(a)

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