INDEX EXCEEDS MATRIX DIMENSION??

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Drishya 2014-2-14

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/116093-index-exceeds-matrix-dimension

编辑： Kristopher 2014-2-14

%while running this function,i got an error message like this... %%%%doing KWFLICM

function [G1,U1]=calculateG(U1,D1,I1,m1,c,C)
[m,n]=size(I1);
G1=cell(m,n);
for i=1:m
  for j=1:n
      G1{i,j}=zeros(c,1);
  end
end
for i=1:m
  for j=1:n
      for k=1:c
          temp=0;
          for x=i-1:i+1
              for y=j-1:j+1
                  q=1;
                  if x>0&&x<m&&y>0&&y<n&&(x~=i||y~=j)
                      d=sqrt((i-x)^2+(j-y)^2);
                      %                          temp=temp+1/(1+d)*(1-U1{x,y}(k,1))^m1*(I1(x,y)-V2(k))^2;
                      %                          temp=temp+C{i,j}(1,q)*(1-U1{x,y}(k,1))^m1*(I1(x,y)-V2(k))^2;
                      temp=temp+1/(1+d)*C{i,j}(1,q)*(1-U1{x,y}(k,1))^m1*(1-D1{x,y}(k,1));
                      q=q+1;
                  end  end end
          G1{i,j}(k,1)=temp;
          G(k)=temp;
      end
      for k=1:c
          temp=0;
          for z=1:c
              %                 temp=temp+(G(k)/G(z))^(1/(m1-1));
              a=1-D1{i,j}(z,1)+G(z);
              if a~=0
                  temp=temp+((1-D1{i,j}(k,1)+G(k))/a)^(1/(m1-1));
              else
                  temp=temp+((1-D1{i,j}(k,1)+G(k))/0.01)^(1/(m1-1));
              end end
          if temp~=0
              U1{i,j}(k,1)=1/temp;
          else
              U1{i,j}(k,1)=1;
          end
      end
  end
end

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Matt J 2014-2-14

What does the DBSTOP command tell you?

Kristopher 2014-2-14

编辑：Kristopher 2014-2-14

which line of code returns the error? Your code is pretty hard to read, but I would guess one of the loops that loops to index+1 is going past the bounds(end) or your matrix for that dimension.

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