sprintf inputs

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joseph Frank
joseph Frank 2011-7-14
Hi,
I am writing a function to determine the shape of a table I want to obtain where one of the inputs in the function is n,which specifies the number of decimal points that I want to have in the function: if in this function I am using: Table1{1,2}=sprintf('%.4f',s.beta(1,1)) to get 4 decimal points in the table, how can i replace the 4f by nf if my n=4,which enables me to play with the table later on if i want to change the number of decimal points for example to n=3;

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Walter Roberson
Walter Roberson 2011-7-14
sprintf('%.*f',n,s,n,beta(1,1))
Notice that the field width is replaced each time the format string is passed through, with it being passed through multiple times if there are more items to output than there are format specifiers.
Alternately,
fmt = sprintf('%%.%df', n);
sprintf(fmt, s, beta(1,1));
  2 个评论
Nathan Greco
Nathan Greco 2011-7-14
Note that it's s.beta(1,1), not s, beta(1,1).
One could just as easily do
fmt = ['%.' num2str(n) 'f'];
sprintf(fmt, s.beta(1,1));
Walter Roberson
Walter Roberson 2011-7-15
Ah, I didn't look closely enough. In that case the code would be
sprintf('%.*f', n, s.beta(1,1))
num2str() has a lot of overhead compared to sprintf()

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