Nested for loop still not working...

Question

Justin 2014-2-18

1
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/116665-nested-for-loop-still-not-working

评论： Justin 2014-2-19

Why will this work...

if true
  % code
end  
InstNames = fieldnames(HistData);
HistData.(InstNames{1}).(DataNames{1}) = SepHistData(:,1,1);
HistData.(InstNames{1}).(DataNames{2}) = SepHistData(:,2,1);
HistData.(InstNames{1}).(DataNames{3}) = SepHistData(:,3,1);
HistData.(InstNames{1}).(DataNames{4}) = SepHistData(:,4,1);
HistData.(InstNames{1}).(DataNames{5}) = SepHistData(:,5,1);
HistData.(InstNames{1}).(DataNames{6}) = SepHistData(:,6,1);
HistData.(InstNames{1}).(DataNames{7}) = SepHistData(:,7,1);
HistData.(InstNames{2}).(DataNames{1}) = SepHistData(:,1,2);
HistData.(InstNames{2}).(DataNames{2}) = SepHistData(:,2,2);
HistData.(InstNames{2}).(DataNames{3}) = SepHistData(:,3,2);
HistData.(InstNames{2}).(DataNames{4}) = SepHistData(:,4,2);
HistData.(InstNames{2}).(DataNames{5}) = SepHistData(:,5,2);
HistData.(InstNames{2}).(DataNames{6}) = SepHistData(:,6,2);
HistData.(InstNames{2}).(DataNames{7}) = SepHistData(:,7,2);

and this won't...

if true
  % code
end
for k = length(InstNames)
  for i = length(DataNames)
  HistData.(InstNames{k}).(DataNames{i}) = SepHistData(:,i,k);
  end
end

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Answer 1

Paul 2014-2-18

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/116665-nested-for-loop-still-not-working#answer_124821

编辑：Paul 2014-2-18

在 MATLAB Online 中打开

You should do

for k = 1:length(InstNames)
  for i = 1:length(DataNames)

So add the 1:. This:

for k = length(InstNames)

assigns the value length(InstNames) to k without looping.

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Justin 2014-2-19

Thanks so much. These are the moments when one is reminded he's a beginner (I feel like exclaiming, DUH!).

Thanks, again.

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Answer 2

Sean de Wolski 2014-2-18

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链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/116665-nested-for-loop-still-not-working#answer_124818

在 MATLAB Online 中打开

length(DataNames)

Will return something like seven I imagine.

Your for-loops will eventually want

SepHistData(7,7)

Which doesn't exist. This is not one of the options above

It seems to me like you want:

for k = 1:2
  for i = 1:length(DataNames)
     etc.

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Justin 2014-2-18

在 MATLAB Online 中打开

Sorry, that was a bad example, this is what I am really working with.

if true
  % code
end
for k = length(InstNames)
  for i = length(DataNames)
  HistData.(InstNames{k}).(DataNames{i}) = SepHistData(:,i,k);
  end
end   
clearvars i k