How do i solve this situation?
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I have list of file like this.
trj.hst.00.+00
trj.hst.01.+00
trj.hst.02.+00
trj.hst.03.+00
...
So, I want to use while loop and The number of files is not fixed
I do not know whether to use some functions.
Are as follows: The code I wrote
c=0;
while (?)
file = sprintf('trj.hst.%02d.+00',c);
fid = fopen(file);
tline = fgetl(fid);
while ischar(tline)
matches = strfind(tline, '#');
num = length(matches);
if num > 0
tline = fgetl(fid);
else
B_temp = tline;
B = fscanf(fid, '%g %g %g %g %g %g %g %g', [8 inf]);
tline = fgetl(fid);
end
end
fclose(fid);
B2 = str2num(B_temp);
B = B';
res = [B2; B];
DATA(1,c).res = res;
% DATA.res_tline = B_temp;
c=c+1;
end
Thanks in advance.
采纳的回答
Use the output fid (fileID) from fopen for your while condition. When the while loop gets to the end of the list, if the file does not exist then fopen cannot open the file and fileID is -1.
Only use the functions when fopen successfully opens a file, i.e. when it returns a file identifier greater >= 3
fid=0; c=0;
while fid ~= -1
file = sprintf('trj.hst.%02d.+00',c);
fid = fopen(file);
if fid < 3 continue; end
disp(['MIHYUN: Reading ' file])
tline = fgetl(fid);
while ischar(tline)
matches = strfind(tline, '#');
num = length(matches);
if num > 0
tline = fgetl(fid);
else
B_temp = tline;
B = fscanf(fid, '%g %g %g %g %g %g %g %g', [8 inf]);
tline = fgetl(fid);
end
end
fclose(fid);
B2 = str2num(B_temp);
B = B';
res = [B2; B];
DATA(1,c).res = res;
DATA.res_tline = B_temp;
c=c+1;
end
更多回答（1 个）
Jos (10584)
2014-2-19
This problem is composed of smaller problems that you may or may not have solved. You can at least tackle them one by one
Problem 1 - How to get the list of files
You can collect them all at once using dir
Myfiles = dir('tr.hst.*.+00') ;
Problem 2 - Load a single file
filename = ...
fid = fopen(filename)
% load the data
res = … % your code here
fclose(fid)
Problem 3 - Get the data of all the files
for k=1:numel(Myfiles)
filename = MyFiles(k).name ;
% code from problem 2 here
DATA(k).res = res ;
end
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