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FRF

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Shrinivas Gombi
Shrinivas Gombi 2011-7-15
[EDIT: 20110715 11:09 CDT - reformat - WDR]
Pl refer to my program:
FORCE=zeros(100,2);
force=zeros(100,2);
for i=1:1:100
m=[H11(i);H21(i)];
n=[H12(i);H22(i)];
frf=[m n];
ffa=[ffa8N(i);ffa10(i)];
FORCE(i,:)=((pinv(frf))*ffa)';
end
force=ifft(FORCE);
force1 =abs(force)*2*pi;
The size of each H11, H12, H21 & H22 is 100x1. I am expecting for each 'i', size of m & n as 2x1, frf as 2x2, ffa as 2x1 and FORCE as 100x2 after transpose. But after the execution I am getting the values for m as [0.187360711350596 - 0.187368466530122i;0.062364375280542 - 0.071296744823281i], and n =[0.208682881606008 + 0.032714463326169i;0.075214194977190 + 0.006696042485398i], ffa =[0.049257402925950 + 0.171256267255695i;-0.068058800649110 + 0.194757769808916i] and frf as [0.187360711350596 - 0.187368466530122i,0.208682881606008 + 0.032714463326169i;0.062364375280542 - 0.071296744823281i,0.075214194977190 + 0.006696042485398i]
I am sure there is some serious mistake in the program. I sincerely request you to kindly help me in locating the logical mistake.
Shrinivas Gombi
  1 个评论
bym
bym 2011-7-15
I don't understand; the sizes you are expecting are the sizes you are getting. m,n,ffa are all 2x1 and frf is 2x2. they are just complex valued

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