What does the function 'norm' do?
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Please tell me what does the 2(in bold) in the below expression mean?
residsumsq = norm(y-yhat, 2 )^2;
Also, Is the norm function referring to summation? I read the documentation but it is not clear.
采纳的回答
Walter Roberson
2014-2-21
n = norm(X) returns the 2-norm of input X and is equivalent to norm(X,2). If X is a vector, this is equal to the Euclidean distance. If X is a matrix, this is equal to the largest singular value of X.
The 2-norm is equal to the Euclidean length of the vector.
So it norm(x) is norm(x,2) is sqrt(sum(x.^2))
更多回答（2 个）
Bruno Pop-Stefanov
2014-2-21
8 个投票
The second input argument of the "norm" function specifies the order of the norm you would like to use. The default norm is the 2-norm, which is the Euclidean distance.
The p-norm is the p-th root of the sum of the terms elevated to the p-th power, i.e.:
3 个评论
Priya
2014-2-21
Walter Roberson
2014-2-21
No, it would be
SS_res = ∑(y-yhat)^2
There would normally be a sqrt() around the sum() but you then square the result of the norm, so that cancels out the sqrt()
Priya
2014-2-21
dpb
2014-2-21
0 个投票
It's the order of the norm requested, in this case the "2-norm" which is the same thing as the Euclidean norm...
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