reshape a matrix with a divisible of 10....

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Elysi Cochin
Elysi Cochin 2014-2-26
评论： Elysi Cochin 2014-2-26
i wanted to reshape my a matrix of size 1*N into 10 rows N/10 columns... but when N is not divisible by 10 i get error... how can i rectify the error?? either pad it with zeros to get a number divisible by 10 or get the previous number divisible by 10....
that is if my matrix
A = 1 * 100
i need output B to be 10*10 output
but if A = 1*111....
i get error, so i want to convert
A to 1 * 120 and get B = 10*12 or
change A to 1*110 and get B = 10*11 new output....
please do reply me....

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采纳的回答

Andrei Bobrov
Andrei Bobrov 2014-2-26
编辑：Andrei Bobrov 2014-2-26
r = 10;
out = reshape([A(:);nan(mod(-numel(A),r),1)],r,[])
ADD
out = reshape(A(1:fix(numel(A)/r)*r),r,[])
  2 个评论
Elysi Cochin
Elysi Cochin 2014-2-26
编辑：Elysi Cochin 2014-2-26
sir which one should i do... isnt both the out variable is same??? what is the difference??
Andrei Bobrov
Andrei Bobrov 2014-2-26
This is a different solutions, for example:
A =randi(25,1,27)
r = 10;
out1 = reshape([A(:);nan(mod(-numel(A),r),1)],r,[]) % first variant
out2 = reshape(A(1:fix(numel(A)/r)*r),r,[]) % second variant

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更多回答（3 个）

Azzi Abdelmalek
Azzi Abdelmalek 2014-2-26
编辑：Azzi Abdelmalek 2014-2-26
A=rand(87,1);
n=(10-mod(numel(A),10));
n=n*sign(n);
A(end+1:end+n)=0;
out=reshape(A,10,[])
%or
r=10
m=numel(A);
out=reshape([A;zeros(ceil(m/r)*r-m,1)],r,[])
Iain
Iain 2014-2-26
To pad it with 0's:
if mod(numel(A),10)
A(ceil(numel(A)/10)*10) = 0;
end
B = reshape(A,10,[]);
To pad with NaNs...
if mod(numel(A),10)
A(end+1:ceil(numel(A)/10)*10) = NaN;
end
B = reshape(A,10,[]);
To use the previous divisible:
A((floor(numel(A)/10)*10+1):end) = [];
B = reshape(A,10,[]);
Anuj
Anuj 2014-2-26
Try this, its very simple-
n=10-mod(numel(A),10);
if n==10;
reshape(A,10,numel(A)/10)
else
A=padarray(A,[0,n],'post');
reshape(A,10,numel(A)/10)
end

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