Reading out a Vector via a countermodel in simulink

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David 2014-2-26

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评论： David 2014-2-26

Hi,

i have to give the single elements of a vector one after the other out. So I decided to build a countermodel.

The Counter works i connected it to a scope and it Counts up in steps of 0.01sec from 0 up to 39. It gives out the variable n.

Then i connected n to the following user-defined function:

Vector=[207;160;0;0;0;6;4;7;10;14;0;44;122;224;16;32;0;16;144;80;128;128;197;167;14;0;0;15;15;0;0;0;0;86;116;235;10;65;241]; Output=Vector(n,1);

The Output of the user-definned function is connected to a scope because i want to test if it works but when i start the Simulation i get following error:

Simulation stopped due to out of bounds error. Block MATLAB Function (#112) While executing: none

Can anyone help me?

Thanks a lot!

Greetings

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Answer 1

Mischa Kim 2014-2-26

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编辑：Mischa Kim 2014-2-26

在 MATLAB Online 中打开

David, are you specifying a value for n? For example (for testing purposes) use the following Simulink model

with the following code inside the MATLAB function.

 function y = fcn(n)
 Vector = [207;160;0;0;0;6;4;7;10;14;0;44];  % vector cut off for readability
 y      = Vector(n,1);

You could specify n in the MATLAB function, or, as an external input for the function.

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Mischa Kim 2014-2-26

Make sure that you are indexing correctly. The first element of the vector is Vector(1), the last is Vector(39).

I am not sure, how you are doing the counting, but if you are using a standard Simulink counter, by default the initial output is 0. This can be "fixed" by simply adding a constant 1 to the counter output. If you do so, make sure the counter quits (limit) at 38 ( + 1 = 39 ).

David 2014-2-26