Reading out a Vector via a countermodel in simulink
6 次查看(过去 30 天)
显示 更早的评论
Hi,
i have to give the single elements of a vector one after the other out. So I decided to build a countermodel.
The Counter works i connected it to a scope and it Counts up in steps of 0.01sec from 0 up to 39. It gives out the variable n.
Then i connected n to the following user-defined function:
Vector=[207;160;0;0;0;6;4;7;10;14;0;44;122;224;16;32;0;16;144;80;128;128;197;167;14;0;0;15;15;0;0;0;0;86;116;235;10;65;241]; Output=Vector(n,1);
The Output of the user-definned function is connected to a scope because i want to test if it works but when i start the Simulation i get following error:
Simulation stopped due to out of bounds error. Block MATLAB Function (#112) While executing: none
Can anyone help me?
Thanks a lot!
Greetings
0 个评论
采纳的回答
Mischa Kim
2014-2-26
编辑:Mischa Kim
2014-2-26
David, are you specifying a value for n? For example (for testing purposes) use the following Simulink model
with the following code inside the MATLAB function.
function y = fcn(n)
Vector = [207;160;0;0;0;6;4;7;10;14;0;44]; % vector cut off for readability
y = Vector(n,1);
You could specify n in the MATLAB function, or, as an external input for the function.
3 个评论
Mischa Kim
2014-2-26
Make sure that you are indexing correctly. The first element of the vector is Vector(1), the last is Vector(39).
I am not sure, how you are doing the counting, but if you are using a standard Simulink counter, by default the initial output is 0. This can be "fixed" by simply adding a constant 1 to the counter output. If you do so, make sure the counter quits (limit) at 38 ( + 1 = 39 ).
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Event Functions 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!