how to get updated value of function everytime in the loop

Question

upinderjeet 2014-2-28

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/119478-how-to-get-updated-value-of-function-everytime-in-the-loop

评论： upinderjeet 2014-2-28

采纳的回答： Walter Roberson

Hello. I am using the below code in the loop and here is the problem area. When I use the code(following)

for i=1:100,

G=i;

A=[-1/10 0;G -(1+10*G)/10];

B=[2 2 0;2 G G];

C=[1 -1];

I=[1 0;0 1];

syms s

Q=C*((s*I-A)^(-1))*B;

Q(2);

Q(3);

syms t

M=(ilaplace(Q(2),s,t))^2;

N=(ilaplace(Q(3),s,t))^2;

m=integral(M,0,Inf);

n=integral(N,0,Inf);

Sw=1;Sv=100;

Ess(i,:)=Sw*m+Sv*n;

We(i,:)=Sw*m;Ve(i,:)=Sv*n;

end

Error using integral (line 83) First input argument must be a function handle.

*now i think the error is in the line where I use M=(ilaplace(Q(2),s,t))^2; and N=(ilaplace(Q(3),s,t))^2;, but how else I can achieve to calculate the integral as each time the value of G is different in each loop and hence I cannot write M and N as function of t because it changes every time the loop is executed depending on the value of G. *

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Walter Roberson 2014-2-28

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/119478-how-to-get-updated-value-of-function-everytime-in-the-loop#answer_126478

编辑：Walter Roberson 2014-2-28

ilaplace is a symbolic transform, giving you a symbolic result. You need to convert the symbolic result to a function handle. See matlabFunction() for that.

Or you could consider using symbolic integration, int() instead of integral()

2 个评论
显示无隐藏无

upinderjeet 2014-2-28

Dont you think that in both the cases you recommend, I still have to write the expression for that symbolic function before I cud use a function handle or int. If I am right then how can I cater to the changing value of that expression every time the new loop is being executed.

upinderjeet 2014-2-28