How can I convert a matrix into a number?

Question

Jaybee 2014-3-12

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/121226-how-can-i-convert-a-matrix-into-a-number

评论： Sagar Damle 2014-3-12

采纳的回答： Mischa Kim

suppose I have a matrix:

matrix=[1 1 0 1 0 1 1]

then I want it to be

1101011.

I used mat2str, num2str but it didn't satisfied me.

Thankyou! More power to you guys!

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

per isakson 2014-3-12

Try the function sprintf

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Mischa Kim 2014-3-12

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/121226-how-can-i-convert-a-matrix-into-a-number#answer_128008

编辑：Mischa Kim 2014-3-12

在 MATLAB Online 中打开

Use

 matstr = strrep(num2str(matrix),' ','')
 bin2dec(matstr)
 ans =
   107

2 个评论
显示无隐藏无

Jaybee 2014-3-12

this helps! thankyou! ive learned a new code :)

Sagar Damle 2014-3-12

If your problem is to get 107 from [1 1 0 1 0 1 1],then you can read this :- There are many functions in MATLAB to convert base 10 to base 2 of a number –

1. dec2base()

2. dec2bin()

3. de2bi()

4. dec2binvec()

However,outputs of these are are not in same format. Run this code on your computer for understaning purpose. See help about these functions in MATLAB.

Note : '0' represents ASCII value of zero(0) which is 48. So,

ans2 = dec2base(4,2) - '0'

is same as

ans2 = dec2base(4,2) – 48

Play with these functions! ENJOY!

% Program -

temp1 = dec2base(4,2)

ans1 = str2num(dec2base(4,2))

ans2 = dec2base(4,2) - '0'

temp2 = dec2bin(4)

ans3 = dec2bin(4) - '0'

temp3 = de2bi(4)

temp4 = de2bi(4,'right-msb')

ans4 = de2bi(4,'left-msb')

temp5 = dec2binvec(4)

ans5 = seqreverse(dec2binvec(4))

whos

请先登录，再进行评论。

Answer 2

per isakson 2014-3-12

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/121226-how-can-i-convert-a-matrix-into-a-number#answer_128009

在 MATLAB Online 中打开

Try

    >> sprintf( '%1d', matrix )
    ans =
    1101011

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。