how to efficiently update one element in a matrix conditioned on another element
1 次查看(过去 30 天)
显示 更早的评论
Hi,
Do you know how to do this? I have a matrix M=[2,3,2;-1,2,3]. I would like to check in any row, if there is a number is less than 0. If so, I let the second column of that row is equal to -Inf. So in this case, as M(2,1)<0.So I update M as [2,3,2;-1,-Inf,3].
I understand I probably can write a loop to do so. But the problem is I need to deal with a big matrix other than M here, which is only 2*3. I will like to speed up the process. So I would like to know if there is an more efficient way to do so? Could any one help me about this please?
0 个评论
采纳的回答
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Resizing and Reshaping Matrices 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!