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problem with the setdiff function

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alex
alex 2014-3-17
评论： alex 2014-3-17
Hello!
i have a problem here
A = 2:.1:15
B=[9.4000 10.4000]
C=setdiff(A,B)
the elements 9.4000 and 10.4000 are still in the C
however,if B=[9.3000 10.3000] then the setdiff works fine,and the elements are not in the C.
any idea why this happens?

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Azzi Abdelmalek
Azzi Abdelmalek 2014-3-17
编辑：Azzi Abdelmalek 2014-3-17
  3 个评论
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Azzi Abdelmalek
Azzi Abdelmalek 2014-3-17
编辑：Azzi Abdelmalek 2014-3-17
Use some tolerance
A = 2:.1:15
B=[9.4000 10.4000 1000]
tol=0.0001
s=abs(bsxfun(@minus,A',B))<tol
[ii,jj]=find(s==1);
A(ii)=[]
alex
alex 2014-3-17
thank you very much!
it works excellent!

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更多回答（1 个）

Jos (10584)
Jos (10584) 2014-3-17
A = 2:.1:15
B = [9.4000 10.4000]
D = 2 ; % number of digits that should match (e.g. 1.231 = 1.229)
C = setdiff(round(A*10^D),round(B*10^D)) ./ (10^D)

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