problem with the setdiff function

9 次查看（过去 30 天）
alex
alex 2014-3-17
评论： alex 2014-3-17
Hello!
i have a problem here
A = 2:.1:15
B=[9.4000 10.4000]
C=setdiff(A,B)
the elements 9.4000 and 10.4000 are still in the C
however,if B=[9.3000 10.3000] then the setdiff works fine,and the elements are not in the C.
any idea why this happens?

请先登录，再回答此问题。

采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2014-3-17
编辑：Azzi Abdelmalek 2014-3-17
  3 个评论
显示 1更早的评论
Azzi Abdelmalek
Azzi Abdelmalek 2014-3-17
编辑：Azzi Abdelmalek 2014-3-17
Use some tolerance
A = 2:.1:15
B=[9.4000 10.4000 1000]
tol=0.0001
s=abs(bsxfun(@minus,A',B))<tol
[ii,jj]=find(s==1);
A(ii)=[]
alex
alex 2014-3-17
thank you very much!
it works excellent!

请先登录，再进行评论。

更多回答（1 个）

Jos (10584)
Jos (10584) 2014-3-17
A = 2:.1:15
B = [9.4000 10.4000]
D = 2 ; % number of digits that should match (e.g. 1.231 = 1.229)
C = setdiff(round(A*10^D),round(B*10^D)) ./ (10^D)

类别

在 Help Center 和 File Exchange 中查找有关 Data Import from MATLAB 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by