problem with the setdiff function
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Hello!
i have a problem here
A = 2:.1:15
B=[9.4000 10.4000]
C=setdiff(A,B)
the elements 9.4000 and 10.4000 are still in the C
however,if B=[9.3000 10.3000] then the setdiff works fine,and the elements are not in the C.
any idea why this happens?
采纳的回答
Azzi Abdelmalek
2014-3-17
编辑:Azzi Abdelmalek
2014-3-17
3 个评论
Azzi Abdelmalek
2014-3-17
编辑:Azzi Abdelmalek
2014-3-17
Use some tolerance
A = 2:.1:15
B=[9.4000 10.4000 1000]
tol=0.0001
s=abs(bsxfun(@minus,A',B))<tol
[ii,jj]=find(s==1);
A(ii)=[]
更多回答(1 个)
Jos (10584)
2014-3-17
A = 2:.1:15
B = [9.4000 10.4000]
D = 2 ; % number of digits that should match (e.g. 1.231 = 1.229)
C = setdiff(round(A*10^D),round(B*10^D)) ./ (10^D)
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