Compute FFT consecutively in Matlab
显示 更早的评论
I have an array of numbers in variable "filter". I wanted to compute Fourier Transform (fft) on every 32 data consecutively using matlab. But the codes below doesn't seems to work. Anyone have a better solution?
for aa=1:length(filter)-32 %scans every row of numbers
output(aa) = fft(filter(aa + (0:31))); % compute fft every 32 data continuously
end
回答（2 个）
Youssef Khmou
2014-3-18
hi, First remark is the name of the variable "filter" is built-in function, this will lead to ambiguity, the other problem is you are iterating with a step of 32 points but you expect to store 32 points in 1 element, the partition in the right must be the same in the left :
for aa=1:length(X)-32 %scans every row of numbers
output(aa+(0:31)) = fft(X(aa + (0:31)));
end
output is complex vector.
Greg Heath
2014-3-18
0 个投票
output(aa) is a scalar
output(aa,:) is a row vector
Hope this helps.
Thank you for formally accepting my answer
Greg
1 个评论
Youssef Khmou
2014-3-18
this is another option to store nx32 matrix like a spectrogram.
类别
在 帮助中心 和 File Exchange 中查找有关 Time-Frequency Analysis 的更多信息
2014-3-18
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
