how many parameters can accept a function in MATLAB?

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JULIO Campos
JULIO Campos 2014-3-18
评论： Walter Roberson 2016-10-27
My function has 6 parameters and I get an error 'Too many input argument'

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回答（2 个）

Walter Roberson
Walter Roberson 2014-3-18
65500 would be the upper limit.
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Adam
Adam 2016-10-27
It's probably a sign that something is maybe wrong in your software designing though if you need 65500 input arguments :)
Walter Roberson
Walter Roberson 2016-10-27
Not necessarily. Remember that the way to efficiently fprintf() a bunch of items with different formats is to put each item into its own cell and then fprintf(fid, format, TheCell{:}) . One should not have to know that there is a magic upper bound beyond which it is needed to break it into pieces.
For example,
str = cellstr( perms('abcde') );
idx = num2cell((1:size(str,1)));
out = [idx; str.'];
fprintf(fid, '%7d: %s', out{:});
One should not have to know that 'abcdefg' could be handled this way but that 'abcdefgh' had to switch strategies due to crossing a magic boundary around 65000 entries.

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Gaurav Shukla
Gaurav Shukla 2014-3-18
I have tried with 13 parameters and it worked.
The error that u have mentioned will appear if your calling function is passing more parameters than the called function can receive.
Ex: function Called(Arg1, Arg2) end
function Calling () Called(Arg1,Arg2,Arg3) end
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Prachi Agarwal
Prachi Agarwal 2016-10-26
output = stegno(img,msg,enc_key,FileName_msg);//calling syntax
function [J] = stegno(img,msg,enc_key,FileName_msg) //function signature
Prachi Agarwal
Prachi Agarwal 2016-10-26
Thank you Adam my code is now working fine. Still, i don't know what was the error.

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