why fplot take more time to run here?

2 次查看(过去 30 天)
Here is the line of code. my Question is why does #2 take more time than #1. 1) fplot('sin(x)',[0 2*pi],1e-2) 2) fplot('sin(x)',[0 2*pi],1e-6) Thanks

回答(1 个)

Star Strider
Star Strider 2014-3-20
编辑:Star Strider 2014-3-20
From the documentation for fplot:
-----
fplot(fun,limits,tol) plots fun using the relative error tolerance tol (the default is 2e-3, i.e., 0.2 percent accuracy).
. . .
fplot uses adaptive step control to produce a representative graph, concentrating its evaluation in regions where the function's rate of change is the greatest.
-----
It seems to me that a tolerance of 1E-6 would require more steps — and therefore more time to execute — than a tolerance of 1E-2.

类别

Help CenterFile Exchange 中查找有关 Surface and Mesh Plots 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by