How to calculate appropriate compression factor?

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Moon Shadow 2014-3-21

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评论： Image Analyst 2014-3-25

If I have an image size 3 inches x 4 inches stored in my computer with the resolution of 1200 dpi.

What is the appropriate compression factor, if this image has to be displayed on a screen of size 6 inches by 8 inches having a resolution of 200 lines per inch and 200 dots per line.

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Image Analyst 2014-3-22

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编辑：Image Analyst 2014-3-22

Try this: http://www.mathworks.com/matlabcentral/answers/8626-how-do-i-get-help-on-homework-questions-on-matlab-answers

Calculate how many dots are in the original image, and how many can be displayed on the screen. You don't need more than you can display. Compression factor uses the ratio of those numbers of dots. You should be able to figure it out!

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Moon Shadow 2014-3-23

编辑：Moon Shadow 2014-3-23

I think to calculate the compression factor it should be both the same unit.

So, I want to convert all the units to Dpi.

The lines per inch and dots per line to Dpi.

Image Analyst 2014-3-23

What does DPI have to do with compression? Magnification yet, but compression? What if I have a 3600 x 4800 pixel image and I display it at 1 dpi on the jumbotron at a stadium? If my image compressed by 1200 to 1? No.

A line pair requires one line to be bright and one line to be dark. Two rows (lines) - that's a line pair . So you need two rows to get a single line pair. That's where your factor of 2 comes from. But it has nothing to do with what we're talking about.

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Walter Roberson 2014-3-23

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You should be treating the display as one vertical pixel per line.

You should be able to calculate the resizing easily enough. You are doubling the horizontal and vertical sizes, which would stretch the 1200 dpi out to 600 dpi. The display is only capable of 200 dpi so you need to subsample by a factor of 3.

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Walter Roberson 2014-3-25

No, subsampling and compression are not the same thing. To do the required display you need to subsample, not to compress.

If you were to take the image and put it through lossy JPEG you could likely get 9:1 compression without much difficulty, but the result would still be a 3600 x 4800 image, which you would not be able to display on a 1200 x 1600 display.

"Compression" is a reduced-memory representation of the same data. What you need is less data, not the same data stored in less computer memory.

Image Analyst 2014-3-25

I agree. Like I said above, you're talking more about magnification (replicating/interpolating pixels, or in your particular case subsampling), rather than compression. Why do you keep wanting to use the term compression? Is there someone who is telling you that compression is the proper term, even though Walter and I are telling you it's not?

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