How to plot exact user defined function?

2 次查看(过去 30 天)
I have defined a function like this
function z=agni(x)
if x > 0
z=x;
else
z = x.^2;
end
But in the time of plotting plot(x,agni(x)) with x =[-2:.01:2] generate only the curve of x^2. WHY?

采纳的回答

Walter Roberson
Walter Roberson 2014-3-25
if x > 0
means
if all(x > 0)
so if you pass in a vector of x then if any x in the vector is <= 0 then the "if" will not be true.
You should research logical indexing.

更多回答(1 个)

Serge Boisse
Serge Boisse 2018-10-27
编辑:Serge Boisse 2018-10-27
Hello, You should understand that your function accepts a vector of values, not a scalar. then it must return a vector of the same length (that will be plotted) So you may rewrite your function as follows :
function z=agni(x)
z = x; % this is a vector !
ind = (x<0); % logical array : 1 if corresponding element of x is <0
z(ind) = z(ind).^2;
end
Hope this helps. If you prefer to code functions "the classical way", have a look at symbolic functions.

类别

Help CenterFile Exchange 中查找有关 Digital Filter Analysis 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by