How to delete leading zeros in a row vector in MATLAB?

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Emily
Emily 2014-3-26
回答： Shivam010 2019-9-8
I have created a function which multiplies two factorials together in MATLAB and the final result is:
0000000000000000000000000000000000000000
0000000000000005127485891768928006848657
3067757467756330382900027197934928341442
4644048874750576347830749966301579885959
6864463688769208320000000000000000000000
00
I need to delete the leading zeros, without deleting the trailing zeros. Anyone know how to do this?
Would help a lot, thanks
  4 个评论
显示 2更早的评论
Walter Roberson
Walter Roberson 2014-3-26
In MATLAB the only way to get a number that long would be by using the Symbolic Toolbox, which would never print leading zeros.
Emily
Emily 2014-3-26
it is a vector, i just put it in the form of a number at the end. I need to know how to get rid of the leading zeros in vector form please?

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采纳的回答

Mischa Kim
Mischa Kim 2014-3-26
If it's a vector of chars, this should do:
data = regexprep(data,'^0*','')

更多回答（3 个）

Joseph Cheng
Joseph Cheng 2014-3-26
So I take it is a string array? If it is I would use something like this.
result='000000000123450101010'
mask = ones(size(result));
zero = strfind(result,'0'); %find all the zeros
mask(zero)=0; %mask off the zeros
msb = find(mask~=0); %find what numbers are not zero in the mak
result=result(msb(1):end) %first non zero number to the end of the result is the number.
Shivam010
Shivam010 2019-9-8
d=[0 0 0 0 0 1 0 0 4 5 0 1]
g=find(d==0)
for i=1:length(g)
if g(i)==i
d(1)=[]
end
end
output:
d =
1 0 0 4 5 0 1
Walter Roberson
Walter Roberson 2017-7-25
编辑：Walter Roberson 2017-7-25
S = '0000000000000000000000000000000000000000000000000000000512748589176892800684865730677574677563303829000271979349283414424644048874750576347830749966301579885959686446368876920832000000000000000000000000';
result = S(find(S ~= '0', 1, 'first') : end);

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