Date conversion in a number format
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Hey guys
I have an excel file with the date format like this: '03/06/2014 11:39:04.324 PM' I want to convert this date format into (yyyymmddhhmmssSSS)20140306233904324. If the time is PM, then the hour should be in the format of 24 hours. Thanks in advance.
采纳的回答
Chandrasekhar
2014-3-27
clc
str = '03/06/2014 11:39:04.324 PM';
[date,rem] = strtok(str,'/');
[month,rem]= strtok(rem,'/');
[year,rem]=strtok(rem,' ');
year = regexprep(year,'/','');
[hours,rem]=strtok(rem,':');
hours = regexprep(hours,' ','');
[mins,rem] = strtok(rem,':');
[sec,rem]=strtok(rem,'.');
sec = regexprep(sec,':','');
[msec,rem]= strtok(rem,' ');
[msec,y] = strtok(msec,'.');
if(strcmp(rem,' PM'))
hours = str2num(hours);
hours = hours+12;
hours = num2str(hours);
end
totaltime = [year date month hours mins sec msec]
更多回答（1 个）
Walter Roberson
2014-3-27
datestr(datevec('03/06/2014 11:39:04.324 PM', 'MM/DD/YYYY hh:mm:ss.fff PM'), 'YYYYMMDDhhmmssfff')
2 个评论
Chandrasekhar
2014-3-27
so simple..
Walter Roberson
2014-3-27
You could also use datenum instead of datevec but I think datevec should be more resistant to round-off.
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