how to reorder the elements of a matrix
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A=[1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16]
i want to reorder the elements of A into
A=[16 15 12 8
11 14 13 10
7 4 3 6
9 5 2 1 ]
6 个评论
Roger Stafford
2014-3-30
What would your pattern be if A were 5x5, 6x6, or nxn? Are you interested in generalizing in that manner?
回答(2 个)
Star Strider
2014-3-29
编辑:Star Strider
2014-3-29
Here’s one solution. I have no idea if it can be generalised to other matrices.
B = flipud(A)
dl = size(A,1);
C = [];
for k1 = sum(size(A))-1 : -1 : 1
dg = diag(B,k1-dl)
if mod(k1,2) == 1
dg = flipud(dg)
end
C = [C; dg]
end
D = reshape(C,size(A))'
0 个评论
Roger Stafford
2014-3-29
Here's a one-liner, though it doesn't exhibit the ingenuity that Star's does.
A = A([16,12,15,14;11,8,4,7;10,13,9,6;3,2,5,1]);
Like Star, I have no idea how this is supposed to generalize. I think you will have to give many more examples or else a more thorough explanation than "zig-zag" if the logic behind this request is to be understood, Alina.
2 个评论
Image Analyst
2014-3-30
编辑:Image Analyst
2014-3-30
Nice and simple. She did not ask for it to be generalized. Hence, this is what she gets as the most direct answer. If she comes back and says "how can I generalize?" then you can say "Well, why didn't you say so in the beginning!?!?"
Sagar Damle
2014-3-30
编辑:Sagar Damle
2014-3-31
I think to generalize the answer for this question,one can work on code for function 'pascal()' available in MATLAB.I have not got the logic in that code uptil now,but though I think that the code will help in zig-zag coding.
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