Create a matrix of binary numbers generated by sequence
显示 更早的评论
I want to create a general matrix to create outputs of the below format...
if n=1
output=[1 0]
if n=2
output=[1 1
1 0
0 1
0 0]
if n=3
output=[1 1 1
1 1 0
1 0 1
1 0 0
0 1 1
0 1 0
0 0 1
0 0 0]
for any number of n; the output matrix will be of the order of [2^n X n]
采纳的回答
the cyclist
2014-3-30
output = dec2bin(2^n-1:-1:0)-'0'
9 个评论
Mohammed
2014-3-30
salma ahmed
2016-1-2
thanks alot :)
poornimasre jegan
2018-6-28
thank you very much. but it is not works when n is large.what should i do if n is more than 30 or 40 etc..?
Ben Krämer
2018-12-14
Thank you very much!
I am quite new to MATLAB and trying to figure out how I can add constraints to your solution.
What I am trying to get, is a Matrix of all the solution for n=8 that contain at least 5 1s.
I hope someone can help me out here.
Bruno Luong
2018-12-14
@Kramer, please open a new thread.
Saber Rahbarfam
2019-1-30
Hello,
Can you please explain what is '0' in this code: output = dec2bin(2^n-1:-1:0)-'0', and what is it doing?
Thanks
Saber
S
2019-3-20
Thank you, 'the cyclist'. That was very clever.
Sodamn Insane
2019-3-27
The -'0' converts the output of dec2bin from a character array with each combination as a row element to a matrix with the type of double.
Muhammad Atif Ali
2021-10-29
this - '0' was the whole trick. I wasted more than 2 hours trying to figure this out.
更多回答（2 个）
Azzi Abdelmalek
2014-3-30
编辑：Azzi Abdelmalek
2014-3-30
n=3;
s=0:1;
idx=rem(nchoosek(0:2^n-1,n),2)+1;
out=flipud(unique(s(idx),'rows'))
görkem tatar
2021-6-18
0 个投票
y =dec2bin(x)
x = 'dec variable'
y = 'convertion of the dec variable to bin'
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