Create a matrix of binary numbers generated by sequence

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Mohammed
Mohammed 2014-3-30
评论： Muhammad Atif Ali 2021-10-29
I want to create a general matrix to create outputs of the below format...
if n=1
output=[1 0]
if n=2
output=[1 1
1 0
0 1
0 0]
if n=3
output=[1 1 1
1 1 0
1 0 1
1 0 0
0 1 1
0 1 0
0 0 1
0 0 0]
for any number of n; the output matrix will be of the order of [2^n X n]

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采纳的回答

the cyclist
the cyclist 2014-3-30
output = dec2bin(2^n-1:-1:0)-'0'
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Sodamn Insane
Sodamn Insane 2019-3-27
The -'0' converts the output of dec2bin from a character array with each combination as a row element to a matrix with the type of double.
Muhammad Atif Ali
Muhammad Atif Ali 2021-10-29
this - '0' was the whole trick. I wasted more than 2 hours trying to figure this out.

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更多回答（2 个）

Azzi Abdelmalek
Azzi Abdelmalek 2014-3-30
编辑：Azzi Abdelmalek 2014-3-30
n=3;
s=0:1;
idx=rem(nchoosek(0:2^n-1,n),2)+1;
out=flipud(unique(s(idx),'rows'))
görkem tatar
görkem tatar 2021-6-18
y =dec2bin(x)
x = 'dec variable'
y = 'convertion of the dec variable to bin'

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