Help with interpolation function

2014 4 1
2 个回答
更新时间：2014 4 1
2 次查看（30 天）

0 个投票

I have set a monotonic function as an array as the following, with x values in the first column and y in the second;
CDF_array =
-4.0000 0
-3.0000 0.1000
-1.0000 0.4000
1.0000 0.6000
3.0000 0.9000
4.0000 1.0000
How do I interpolate to find the x-values at y=0.05, y=0.15 and y=0.63?

请先登录，再回答此问题。

回答（2 个）

Star Strider
Star Strider 2014-4-1

0 个投票

With:
CDF = [ -4.0000 0
-3.0000 0.1000
-1.0000 0.4000
1.0000 0.6000
3.0000 0.9000
4.0000 1.0000];
this statement:
xi = interp1(CDF(:,2), CDF(:,1), [0.05; 0.15; 0.63])
produces:
xi =
-3.5000e+000
-2.6667e+000
1.2000e+000
the cyclist
the cyclist 2014-4-1

0 个投票

CDF_array = ...
[-4 0.0;
-3 0.1;
-1 0.4;
1 0.6;
3 0.9;
4 1.0];
y_interp = [0.05 0.15 0.63];
x_interp = interp1(CDF_array(:,2),CDF_array(:,1),y_interp)

类别

在 帮助中心 和 File Exchange 中查找有关 Interpolation 的更多信息

产品

标签

提问:

Felix
Felix
2014-4-1

回答：

the cyclist
the cyclist
2014-4-1

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by