Seperate column into more columns: 90740x1 double array into 1511x64 something array
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Hello
i have a set of data 90740x1 double. meaning:
what i really want this to do is make a new matrix where i read every 1511 data from this row into a new row. example:
so from 1 to 1511 in column 1 in the new matrix...and from 1511 to 3023 into column 2 in the new matrix etc. etc.
i made a code, it only works for the first 1511 data but after that it displays an error about dimension.
n = 1; for i=1:length(kwh) kunder(:,1) = kwh(1:n:1511); end
so when u put: kunder(:,1) = kwh(1511:n:3023); under the first kunder it displays dimension error...
please help me figure this out..as i want to plot the 24 hour kwh usage data of customers consumption of electricity.
thank you
采纳的回答
Kelly Kearney
2014-4-8
Your code is erroring because of mismatched dimensions; when n = 2, 1:n:1511 expands to [1 3 5 ... 1511], which is only 756 elements in length. What you wanted was [1:1511]+1511*(n-1). But it would be more straighforward just using reshape.
x = rand(90740,1);
nrow = 1511;
ncol = ceil(length(x)/nrow);
x = [x; nan(ncol*nrow-length(x),1)];
x = reshape(x,nrow,ncol);
Note that you need to pad with NaNs or 0s or whatever is appropriate, since your number of elements isn't evenly divisible by 1511.
2 个评论
awda
2014-4-8
Kelly Kearney
2014-4-8
How do you figure that? 90740/1511 = 60.053, ie. 60 remainder 80. So you should end up with a 1511 x 61 array, with 80 elements in the final column.
更多回答（1 个）
Azzi Abdelmalek
2014-4-8
Use reshape
reshape(A,1511,64)
3 个评论
awda
2014-4-8
Azzi Abdelmalek
2014-4-8
This is because with 90740 elements you can't get a 1511x64 array which contains 96704 element
Azzi Abdelmalek
2014-4-8
What you can do is to add some nan to your final array
n=90740
A=rand(n,1);
m=ceil(90740/1511)*1511
A(end+1:m)=nan
out=reshape(A,1511,[])
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