put the result in one matrix

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yousef Yousef 2014-4-13

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评论： Star Strider 2014-4-14

Hi,I have ,w=[2 4 4 1 1].
for i=1:length(w)
x=find(w==w(i))
end
this code gives this result:x=[1]',x=[2 3]',x=[4 5]',x=[4 5]',in each iteration.
I want the result to be x=1 0 0 0
                          2 3 0 0
                          4 5 0 0
                          4 5 0 0

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Answer 1

Star Strider 2014-4-13

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Actually, your code does not give the result you post when I run it. The second row, [2 3 0 0] is repeated (as it should be) in the third.

I suggest:

w=[2 4 4 1 1];
x = zeros(4,4);
for i=1:length(w)
    wi = find(w==w(i))
    x(i,1:length(wi))=wi;
end

that produces:

x =
       1     0     0     0
       2     3     0     0
       2     3     0     0
       4     5     0     0
       4     5     0     0

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Le Huy 2014-4-14

编辑：Le Huy 2014-4-14

hello everyone! excuse me! could you please explain the code "x(i,1:length(wi))=wi" to me? i want to know what does the figure "1:length(wi)" mean? thank you!

Star Strider 2014-4-14

LeHuy — The ‘1:length(wi)’ statement creates a vector starting at 1 with spacing of 1 to whatever the length of wi is for that loop. If wi=3, the vector is [1 2 3]. Please see the documentation on the colon ‘:’ operator for more details.

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