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looping a sequence easiest

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Rasmus
Rasmus 2014-4-16
评论： Mischa Kim 2014-4-16
hello guys!
which way would be the easiest to make a loop of a sequence 1000 times ?
this is my code
-------------------------------------------------------
x0=[zeros(1,276) ones(1,290)]; x=x0(randperm(566)); b=(0:566); d=[x 0]-[0 x]; l=(b(d==(-1))-b(d==1)) L=max(l) -------------------------------
I need L in a propability assignment. For that I need 1000 different results and put it into a histogram. So I need the sequence to repeat it self 1000 times.
How do you do that?

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Mischa Kim
Mischa Kim 2014-4-16
编辑：Mischa Kim 2014-4-16
Something like
x0 = [zeros(1,276) ones(1,290)];
L = zeros(1,1000);
b = (0:566);
for ii = 1:1000
x = x0(randperm(566));
d = [x 0] - [0 x];
l = (b(d==(-1)) - b(d==1));
L(ii) = max(l);
end
  2 个评论
Rasmus
Rasmus 2014-4-16
How would you get all the data over in a histgram. For some reason when i say
result=hist(L(ii),1:10)
it only gives me one value in it.
Mischa Kim
Mischa Kim 2014-4-16
Use
result = hist(L)
or
hist(L) % to plot

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