Error using plot--vectors must be the same lengths?

Question

0 个投票

Why am I getting the error message, "Error using plot Vectors must be the same lengths"? This code worked fine before I added a few more data points… Thank you in advance! :)

 % Load      Horiz.Disp.  Vert.Disp.
  A=[0.000000E+0 0.000000E+0  0.000000E+0
735352E-1 -5.517578E-3 -3.906250E-4
489746E-1 -1.005859E-2 -9.765625E-5
575684E-1 -1.054687E-2 7.812500E-4
644531E-1 -1.113281E-2 1.708984E-3
968750E-1 -1.381836E-2 2.734375E-3
428223E-1 -1.835937E-2 2.734375E-3
182324E+0 -2.192383E-2 4.394531E-3
416846E+0 -2.827148E-2 4.150391E-3
622949E+0 -3.500977E-2 3.906250E-3
815039E+0 -4.213867E-2 5.126953E-3
005273E+0 -5.039062E-2 5.664063E-3
201904E+0 -5.966797E-2 5.908203E-3
406152E+0 -7.031250E-2 5.859375E-3
622949E+0 -8.139648E-2 6.005859E-3
858691E+0 -9.526367E-2 5.957031E-3
104980E+0 -1.117676E-1 6.494141E-3
371484E+0 -1.316406E-1 7.226563E-3
663330E+0 -1.607422E-1 6.787109E-3
968652E+0 -1.978027E-1 7.666016E-3
311963E+0 -2.585937E-1 7.226563E-3
648584E+0 -3.464844E-1 8.251953E-3
933789E+0 -4.650879E-1 8.984375E-3
160156E+0 -6.127930E-1 9.472656E-3
314648E+0 -7.623535E-1 9.423828E-3
421826E+0 -9.119141E-1 9.814453E-3
497217E+0 -1.054199E+0 1.054688E-2
550635E+0 -1.184229E+0 1.079102E-2
592627E+0 -1.308594E+0 1.127930E-2
625293E+0 -1.420264E+0 1.191406E-2
677246E+0 -1.631250E+0 1.269531E-2
710596E+0 -1.820898E+0 1.333008E-2
735498E+0 -1.994336E+0 1.420898E-2
754199E+0 -2.154346E+0 1.552734E-2
777881E+0 -2.449365E+0 1.650391E-2
781934E+0 -2.584668E+0 1.728516E-2
781396E+0 -2.712500E+0 1.796875E-2
778418E+0 -2.836328E+0 1.948242E-2
776172E+0 -2.897314E+0 2.011719E-2
765283E+0 -3.072803E+0 2.109375E-2
759521E+0 -3.127002E+0 2.207031E-2
754980E+0 -3.183545E+0 2.304688E-2
733252E+0 -3.396484E+0 2.456055E-2
717334E+0 -3.498437E+0 2.558594E-2
684521E+0 -3.697021E+0 2.705078E-2
664746E+0 -3.790869E+0 2.783203E-2
633740E+0 -3.931055E+0 2.861328E-2
621533E+0 -3.974951E+0 2.934570E-2
598584E+0 -4.064502E+0 3.007813E-2
585693E+0 -4.108057E+0 3.081055E-2
573096E+0 -4.152197E+0 3.159180E-2
535010E+0 -4.279150E+0 3.247070E-2];
  load=(A(:,1)).*100;
  HorizDisp=abs((A(:,2)).*0.19574);
  VertDisp=abs((A(:,3)).*1.724); 
  l=length(load);
  yield=40000; %yield stress = 40 ksi
  b=.125; %b = t = thickness of rod
  h=1; %h = w = width of rod
  L=9.875; %L = length of rod (subtracted out 2 in from 11.875)
  E=10000000; %elastic modulus of Al 6061-T6
  I=h*(b^3)/12; %Moment of Intertia
  P=E*I*4*pi*pi/(L*L); %Buckling (or "critical") Load
  disp(P) %Display value of Buckling Load
for n=1:l
    loadnorm(n)=load(n)/P; %Normalize applied load by dividing by P
end
plot(VertDisp,loadnorm);