floating point to binary conversion

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ashok
ashok 2014-4-28
回答： Walter Roberson 2014-4-28
if true
% code
if a =
-5932.62103114252
5931.17666698258
5797.34103035393
-6358.78042353988
-12430.1210180646
-9849.27324380255
-6386.88118380371
7783.15716000243
5177.38696737792
6082.47763148202
-4816.43707738488...........
end
how to convert this to binary? with out using uint8,16,64 i need the output in double
if i use uint the values are rounded off and i am not able to reconstruct (image) is there any possibilities to convert it.
because after converting it i need to modulate and transmit.

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采纳的回答

Walter Roberson
Walter Roberson 2014-4-28
dec2bin(typecast(YourFloatingPointVector, 'uint64'), 64) - '0'

更多回答（1 个）

Image Analyst
Image Analyst 2014-4-28
I don't know what you mean. The image already is in double. What do you mean by "binary"? You mean binary like a binary image, where the pixels are true or false and the data type is logical? You can create that by thresholding and casting to double:
binaryImage = a < 1000; % Whatever value... binaryImage is of type "logical".
doubleImage = double(binaryImage); % Make double.
What are you talking about uint8, uint16, etc. Those aren't binary except in the sense that ALL numbers in a computer are binary. Maybe you want the dec2bin() function to turns numbers into strings of 0's and 1's.

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