How to rearrange the rows of a matrix?

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MRC
MRC 2014-4-28
回答： Roberto 2014-4-28
Hi, I want to reshape a matrix A of dimension rxc in a matrix B of the same dimension but with rows rearranged following the index in the first column
E.g.
A=[ 1 1 4 7 10; 2 2 5 8 11; 3 3 6 9 12; 4 13 16 19 22; 5 14 17 20 23; 6 15 18 21 24; 1 25 26 27 28; 2 29 30 31 32; 3 33 34 35 36; 4 37 38 39 40; 5 41 42 43 44; 1 46 47 48 49; 2 50 51 52 53; 5 54 55 56 57; 6 58 59 60 61]
I want
B=[1 1 4 7 10; 1 25 26 27 28; 1 46 47 48 49; 2 2 5 8 11;2 29 30 31 32;2 50 51 52 53; 3 3 6 9 12; 3 33 34 35 36; 4 13 16 19 22; 4 37 38 39 40; 5 14 17 20 23; 5 41 42 43 44; 5 54 55 56 57; 6 15 18 21 24; 6 58 59 60 61]
The features of A on which I can rely are:
-the max of the first column is m=6;
-the elements in the first column of A are increasing until m and then they restart;
-each element of the first column of A can appear for at most n=3 times.
I prefer not to use loops.

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采纳的回答

Andrew Newell
Andrew Newell 2014-4-28
The trick is to use the index from sorting the first column:
[~,idx] = sort(A(:,1));
B = A(idx,:);

更多回答（1 个）

Roberto
Roberto 2014-4-28
try accessing the matrices subscripts, for example:
% have this matrix
a =
16 2 3 13
5 11 10 8
9 7 6 12
4 14 15 1
% change the order of rows:
a([3 2 4 1],:)
ans =
9 7 6 12
5 11 10 8
4 14 15 1
16 2 3 13
or simply use the matlab command sort

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