Check for 1 in a array
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Hey
I have a 3x20 array, where I want to check if row 2 contains 1. If not it should state a message. I was thinking on a if & else . But I'm not quite sure how to check for the number 1.
采纳的回答
Here is an example:
A = randi( 10, 3 ,20 ) % Dummy example.
if any( A(2,:) == 1 )
fprintf( 'Found at least one 1 on row 2!\n' ) ;
end
Running it gives:
>> A
A =
Columns 1 through 16
1 7 5 1 6 1 3 10 7 4 4 10 6 9 4 4
3 1 2 3 6 9 1 7 5 9 4 9 2 7 6 7
2 7 4 4 8 4 9 6 10 2 10 2 9 3 8 5
Columns 17 through 20
2 6 1 6
7 8 5 10
6 2 9 7
Found at least one 1 on row 2!
6 个评论
It is because FCA is not a numeric array, but a cell array [ ref ]. Try to convert it to a numeric array first, i.e.:
FCA_num = cell2mat( FCA ) ;
and then work with FCA_num.
Then convert just row 2 if it is the only row involved.
row2 = cell2mat( FCA(2,:) ) ;
if any( row2 == 1 )
...
end
Kasper
2014-5-6
Cedric
2014-5-6
My pleasure.
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