search the second column of a cell array according to the values in the first column

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Sergio Rossi
Sergio Rossi 2014-5-7
编辑： Sergio Rossi 2014-5-7
I'm working in MATLAB and I have the following cell array:
pippo =
'FSize' [ 10]
'MSize' [ 10]
'rho' [ 997]
'u2' [ 86.2262]
'n' [ 100]
'nimp' [ 2]
'impeller1dir' [1x66 char]
'impeller2dir' [1x66 char]
'comparedir' [1x57 char]
I would like to return the content of the cell, in the second column, which corresponds to a given value for the cell in the first column of the first row. I.e., if the input is 'nimp', I want to return 2. Is there a simple way to do this which doesn't involve looping, or is looping the only way?

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采纳的回答

Andrei Bobrov
Andrei Bobrov 2014-5-7
out = pippo{ismember(pippo(:,1),'nimp'),2};
  2 个评论
Sergio Rossi
Sergio Rossi 2014-5-7
编辑：Sergio Rossi 2014-5-7
Great! I was given this solution, too:
out = pippo{strcmp(pippo(:,1),'nimp'),2};
which does the same ( ismember is more generic, though, and works regardless of the types of elements in the first column of parameters ). However, my favourite is:
pippo=containers.Map(pippo(:,1),pippo(:,2))
You can then retrieve any value simply by accessing the container with the corresponding key:
out=pippo2('nimp');
Didn't know MATLAB had containers! Looks like a great solution. What do you think?

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更多回答（1 个）

Roberto
Roberto 2014-5-7
I'd recommend the use of structures:
pippo.FSize= 10;
pippo.MSize= 10;
pippo.rho= 997;
pippo.u2= 86.2262;
So when you want a member, just type:
>> pippo.FSize
ans =
10
but if it cannot be done, try to use a code like this:
pippo = {'test',4;'Some',5} ;
searched = 'some';
returned = [];
for i = 1: numel(pippo)/2
if strcmpi(pippo{i,1},searched)
returned = pippo{i,2};
end
end
disp(returned);

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