Solve equation with 1 unknown numerically

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Niles Martinsen
Niles Martinsen 2014-5-13
回答： Star Strider 2014-5-13
I have the following script that defines a function and sets up and equation:
H = @(f) sum(log(f));
f = rand(1, 1);
syms a
H(f)-H(f-a)
I want to solve H(f)-H(f-a)=0 for a. I tried using fzero in the following manner, fzero('H(f)-H(f-a)', 0), but this doesn't yield me anything useful.

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回答（1 个）

Star Strider
Star Strider 2014-5-13
This works:
H = @(f) sum(log(f));
f = rand(1, 1);
a = fzero(@(a) H(f)-H(f-a), 0)
The value of a is, expectedly, zero.

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