Solve equation with 1 unknown numerically

2014 5 13

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I have the following script that defines a function and sets up and equation:

    H = @(f) sum(log(f));
    f = rand(1, 1);
    syms a
    H(f)-H(f-a)

I want to solve H(f)-H(f-a)=0 for a. I tried using fzero in the following manner, fzero('H(f)-H(f-a)', 0), but this doesn't yield me anything useful.

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Star Strider 2014-5-13

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This works:

      H = @(f) sum(log(f));
      f = rand(1, 1);
      a = fzero(@(a) H(f)-H(f-a), 0)

The value of a is, expectedly, zero.

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