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addtodate: unexpected result when adding years

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Andrew
Andrew 2014-5-19
评论： Star Strider 2014-5-19
Hi all,
I'm having an issue with addtodate.m. The example:
addtodate(1, 2014, 'year')
ans =
-734501
is not what I expected... Does anyone know what's going on?
Notes: I'm trying to use addtodate to sanitize a date vector
datevec_unsan = [2014, 1, 1, 40, 0, 0]; % there aren't 40 hours in a day...
types = {'year', 'month', 'day', 'hour', 'minute', 'second'};
tstamp = 0;
for i = 1:6
tstamp = addtodate(tstamp, datevec_unsan(i), types{i});
end
datevec_sanitized = datevec(tstamp);

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回答（2 个）

the cyclist
the cyclist 2014-5-19
编辑：the cyclist 2014-5-19
I was unaware of this handy function before, but this definitely seems like a bug. The result of
datestr(addtodate(1,2014,'year'))
is '01-Jan-7986', while
datestr(addtodate(1,-2014,'year'))
gives '01-Jan-2014' (which I am guessing is what you expected for your answer originally). Adding just a day or a month seems to work fine, though.
I am about to head out the door, so I can't dig in right now, but you could try
edit addtodate
to poke into the function and see what's going on. I suggest you fill out a bug report, unless someone here points out something obvious that you and I are misunderstanding!
  1 个评论
Andrew
Andrew 2014-5-19
Thanks for looking at this. addtodate uses addtodatemx so I don't think we can look at the source sadly

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Star Strider
Star Strider 2014-5-19
MATLAB will do the correction for you. I don’t know the result you want, but this works:
datevec_unsan = [2014, 1, 1, 40, 0, 0]
x = datenum(datevec_unsan);
datevec_new = datevec(x)
produces:
datevec_unsan =
2014 1 1 40 0 0
datevec_new =
2014 1 2 16 0 0
  2 个评论
Andrew
Andrew 2014-5-19
编辑：Andrew 2014-5-19
Good idea - its even in the datenum documentation that it supports it! And it saves me putting in correction for 1 based days in my original code.
Star Strider
Star Strider 2014-5-19
Thanks!
If it solved your problem, the sincerest form of appreciation her on ‘MATLAB Answers’ is to Accept it.

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