HOW TO ACCESS THE FOLLOWING ELEMENTS FROM THE GIVEN ARRAY

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BIRAJA
BIRAJA 2014-5-21
回答： Andrei Bobrov 2014-5-25
a=
0 0 0.3013 1.1305
1.0000 2.0000 0.7390 0.4223
3.0000 2.0000 1.1305 -0.2111
I need
A1=[[a(1,1) a(2,1) a(1,3) a(2,3)]' [a(1,2) a(2,2) a(1,4) a(2,4)]' ] A2=[[a(2,1) a(3,1) a(2,3) a(3,3)]' [a(2,2) a(3,2) a(2,4) a(3,4)]' ]
  2 个评论
Cedric
Cedric 2014-5-21
What doesn't work with the current approach? Do you need to generalize it to larger arrays? If so, what will be the size of these arrays and what will you want to perform ultimately?
BIRAJA
BIRAJA 2014-5-25
编辑：BIRAJA 2014-5-25
Sir,
I want to access the elements of the given matrix as per the sequence. It can be increased to 50-rows and 50-columns. I want a generalized code.

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回答（2 个）

Andrei Bobrov
Andrei Bobrov 2014-5-25
A1 = reshape(permute(reshape(a(1:end-1,:),2,2,[]),[1,3,2]),[],2);
a02 = [a(:,2:end-1);a(2:end,end)'];
A2 = reshape(permute(reshape(a02',2,2,[]),[1 3 2]),[],2);
George Papazafeiropoulos
a=[ 0 0 0.3013 1.1305;
1.0000 2.0000 0.7390 0.4223;
3.0000 2.0000 1.1305 -0.2111];
A1=[[a(1,1) a(2,1) a(1,3) a(2,3)]' [a(1,2) a(2,2) a(1,4) a(2,4)]' ]
A2=[[a(2,1) a(3,1) a(2,3) a(3,3)]' [a(2,2) a(3,2) a(2,4) a(3,4)]' ]
for i=1:size(a,1)-1
b=a(i:i+1,:);
b=b(:);
n1=1:size(a,2)-1;
b1=b;
ind1=3+cumsum([0,2+(-1).^n1]);
b1(ind1)=[];
b2=b;
ind2=1+cumsum([0,2+(-1).^n1]);
b2(ind2)=[];
A=[b1 b2]
end

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