Plot a 3d-plane in MATLAB??

Question

Nghia 2014-5-22

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/130581-plot-a-3d-plane-in-matlab

编辑： Nghia 2014-5-26

I want to plot a 3d-plane (x=0) in MATLAB, (-2<=y<=2) and limited by the line z=4-y^2. Here's my code :

 y=linspace(-2,2,50);
z=4-y.^2;
[Y Z]=meshgrid(y,z);
X=0*Y+0*Z;
mesh(X,Y,Z);
axis tight;

Can you give me any hints???? thank you very much!!

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Walter Roberson 2014-5-22

编辑：Walter Roberson 2014-5-22

What is the difference between this question and http://www.mathworks.co.uk/matlabcentral/answers/130475-how-to-draw-a-graph-in-3d ?

When you say that the plane is to be limited by that z, and that you want to draw plot it, then what difference is there compared to plotting a single curved line in 3 space?

Nghia 2014-5-22

编辑：Nghia 2014-5-22

I'm not clear what you're trying to ask but the code which I posted plot just a single curved line in 3 space, but what I want is to plot a plane x=0 and limited by both the line z=0 and z=4-y^2 I mean that I want to use to plot a plane surfc(x,y,z)

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Answer 1

Hugo 2014-5-22

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This solution is based on patch

 y=-2:.01:2;
 z=4-y.^2;
 numy=length(y); 
 % Constructing the vertices
 V=zeros(numy,3); 
 for iy=1:numy, 
     V(iy,:)=[0,y(iy),z(iy)];  % Vertices in the parabola 
     V(iy+numy,:)=[0,y(iy),0]; % Vertices in the y axis
 end
 % Constructing faces
 F=zeros(numy-1,4); for iy=1:numy-1, F(iy,:)=[iy,iy+1,iy+1+numy,iy+numy]; end
 patch('Vertices',V,'Faces',F)