How to make an anonymous function whose variable is itself a function of another variable?

2014 5 23
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更新时间：2014 5 23
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Let's say i have an anonymous function defined in the following manner
z = @(x) cos(phi).^2 + 4*sin(phi).^2 and phi is defined in the following way
phi = @(x) x.^3 + 4*x.^2 + x +3
I have been trying to do this but when i call the function z in the following way, an error pops up
z(3)
Is something wrong in the syntax?

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Mischa Kim
Mischa Kim 2014-5-23
编辑：Mischa Kim 2014-5-23

1 个投票

Salman, use
phi = @(x) x.^3 + 4*x.^2 + x + 3;
z = @(x) cos(phi(x)).^2 + 4*sin(phi(x)).^2;
z(3)
ans =
1.039526660425723

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