Simply Directory Question

2011 8 4
3 个回答
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0 个投票

Hello All,
Quick question, I am trying to load all files from a folder that have a .m ext:
folder = C:\Users\ecorbett\Documents\MATLAB\UI\VCoachData\0005_Capture_10072009\AccelData
files = dir(folder)
I know I need to include something like '*.m' in dir but I dont know the correct syntax to do so. Can someone help me with this?

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Paulo Silva
Paulo Silva 2011-8-4

1 个投票

m=dir([folder '\*.m']);
files=arrayfun(@(x)m(x).name,1:numel(m),'uni',false); %or use Oleg suggestion

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Oleg Komarov
Oleg Komarov 2011-8-4
files = {m.name};
Paulo Silva
Paulo Silva 2011-8-4
Thanks Oleg, I always forget that easy way to do it
B_Richardson
B_Richardson 2011-8-4
what is this "name?" Is that my "folder"?
Oleg Komarov
Oleg Komarov 2011-8-4
Check out the documentation for dir. Name is a field of the structure m.
Walter Roberson
Walter Roberson 2011-8-4
No, in this context, "name" is a particular field from the structure returned by dir. m(K).name is the name of the K'th file, but without any parts of the folder name.
Paulo Silva
Paulo Silva 2011-8-4
name is a field of the structure you get from the dir function, each file the dir function accepts creates a new entry on the structure with several fields, name being one of them.
B_Richardson
B_Richardson 2011-8-4
I see! Thank you all! I feel like you guys are my professors sometimes lol
Walter Roberson
Walter Roberson 2011-8-4
Think I'd be able to get Tenure? ;-)
B_Richardson
B_Richardson 2011-8-4
You'd have my vote!

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更多回答（2 个）

B_Richardson
B_Richardson 2011-8-5

0 个投票

Hey guys, I'm still having trouble with this code. I've included the some more to give you a better understanding of what I'm tring to do.
I just want to get a dir (load .mat data files only) and loop through that dir until I match my pattern. Once I match, load construct fullfile.
[pathstr, name, ext] = fileparts(file)
name = 'AccelData';
file2 = fullfile(pathstr,[name])
z=dir([file2 '\*.m']);
files = {z.name}
Pattern=itemselected(1:9)
for i = 1 : numel(files)
value=files(i).name;
if strfind(value,Pattern)
f = fullfile(file2,value)
For some reason,
z=dir([file2 '\*.m']);
files = {z.name}
files is coming up empty. The way I had it before worked:
files = dir(folder)
But of course it included all file types and i just want the matlab data files.

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Oleg Komarov
Oleg Komarov 2011-8-5
z=dir([file2 '*.m']);
without the \
B_Richardson
B_Richardson 2011-8-5
Still comes up empty.
z=dir([file2])
works. But the'*.m' is messing it up
B_Richardson
B_Richardson 2011-8-5
0x1 struct array with fields:
name
date
bytes
isdir
datenum
Oleg Komarov
Oleg Komarov 2011-8-5
can you show what's file2?

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B_Richardson
B_Richardson 2011-8-5

0 个投票

I feel so stupid right now! My files are .mat not .m! AARRRGGGGGG Thanks everybody!!

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