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Help me how to calculate sum of series ?

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Nguyen Trong Nhan
Nguyen Trong Nhan 2014-5-27
编辑： Walter Roberson 2021-6-5
help me how to calculate the sum of a series in Matlab. (for example 2 series in the picture)
  1 个评论
chadi cream
chadi cream 2017-12-22
编辑：Walter Roberson 2017-12-22
symsum((sqrt(n+1) - sqrt(n-1))/n^(3/4),n,1,inf)
vpa(ans)
=5.0311555338624769245497524622442

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回答（4 个）

rifat
rifat 2014-5-27
编辑：rifat 2014-5-27
You can not add infinite number of terms. If the sum is a converging sum, then you can add a large number of terms (e.g. n=5000) to get a satisfactory result.
n=5000;
series1=0;
series2=0;
for i=1:n
p=(((i+1)/i)^i)/(i^2);
series1=series1+p;
p=(sqrt(i+1)-sqrt(n-1))/(i^.75);
series2=series2+p;
end
  2 个评论
Sandie Nhatien Vu
Sandie Nhatien Vu 2016-8-5
@Rifat ahmed is it possible to write a script using vectorized computation instead of the for-loop for that sum of series?

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Roger Wohlwend
Roger Wohlwend 2014-5-27
n = 1 : 10^6;
sum(((n+1)./n).^n./n.^2)
sum((sqrt(n+1) - sqrt(n-1))./n.^(3/4))
  2 个评论
chadi cream
chadi cream 2017-12-22
编辑：Walter Roberson 2021-6-5
syms n;
f=1/n^2*((n+1)/n)^n
symsum(f,n,1,inf)
vpa(ans) = 3.550777333936337795612455939406

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Perwez Alam
Perwez Alam 2018-12-4
How to write editer command to plot (t,g)
Please help me.
thanking You
Kokou Moutchou
Kokou Moutchou 2018-5-1
sqrt(6*((1/1^2)+(1/2^2)+(1/3^2)+...+(1/n^2(

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