for loop indexing and skip numbers

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Damith
Damith 2014-5-28
评论： Abraxas 2019-4-25
Hi,
I need to include for loop in MATLAB to start with 2:13. But I need to start with 2,3,4 and skip 5 and again 6,7,8 and skip 9 and 10,11,12 until 13.
How can I implement this is for loop?
Many thanks in advance.

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采纳的回答

Roger Stafford
Roger Stafford 2014-5-28
You can also use
ix = floor((4*(1:n)+2)/3);
where n is the desired length of the output.

更多回答（3 个）

the cyclist
the cyclist 2014-5-28
for n = [2 3 4 6 7 8 13]
disp(n)
end
  5 个评论
显示 3更早的评论
Abraxas
Abraxas 2019-4-25
I've been searching 2 days for this answer! Thank you so much!

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the cyclist
the cyclist 2014-5-28
Yet another method:
idx = bsxfun(@plus,[1 2 3]',1:4:100)
for ii = idx(:)
disp(ii)
end
the cyclist
the cyclist 2014-5-29
Yet another method:
idx = filter([1 1 1 1],[1 1 1 0],1:100)+1

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