for loop indexing and skip numbers

Hi,
I need to include for loop in MATLAB to start with 2:13. But I need to start with 2,3,4 and skip 5 and again 6,7,8 and skip 9 and 10,11,12 until 13.
How can I implement this is for loop?
Many thanks in advance.

 采纳的回答

You can also use
ix = floor((4*(1:n)+2)/3);
where n is the desired length of the output.

更多回答(3 个)

for n = [2 3 4 6 7 8 13]
disp(n)
end

5 个评论

Thanks. But if I use upto 10000, how can I formulate this? For example,
2,3,4,6,7,8,10,11,12,14,15,16.....10000.
Thanks again.
A nice feature that not many people know about, but more should. It's good that you pointed it out. +1 vote.
idx = setdiff(2:10000,5:4:10000);
for ii = idx
disp(ii)
end
Thanks. It worked.
I've been searching 2 days for this answer! Thank you so much!

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Yet another method:
idx = bsxfun(@plus,[1 2 3]',1:4:100)
for ii = idx(:)
disp(ii)
end

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