How do I add a value in ONE element of a matrix in a for loop?

2014 5 30
2 个回答
回答已采纳
更新时间：2014 5 30
2 次查看（30 天）

0 个投票

Hello, let's say I have a matrix A = [1+x,1;2,5] so I want to have x to go from -20 to 20 with x~=0
then I would need to have A(i) matrices with i=40 . How do I do this on Matlab? I've been reading on internet on indexing and things like that, but I keep getting errors. I really appreciate you taking the time.
Sincerely,

2 个评论
显示 无 隐藏 无

Mahdi
Mahdi 2014-5-30
Does the second row (2,5) get repeated every time? Or does it become, let's say (you have 1 to 3)
A=[1, 1;
2,1;
3,1;
2,5]
Can you show an example of what you want the output to be?
Salar
Salar 2014-5-30
Sure, let's say A = [1+x,1;2,5] , and for simplicity let's have x goes from -2 to 2 with and increment of one and x~=0, so output will look like =
A_1=[-1,1;2,5]
A_2=[0,1;2,5]
A_3=[2,1;2,5]
A_4=[3,1;2,5]

请先登录，再进行评论。

请先登录，再回答此问题。

 采纳的回答

Image Analyst
Image Analyst 2014-5-30

0 个投票

I show you two different methods in the loop below:
counter = 1;
A3D = [];
for x = -20 : 20
if x == 0
continue;
end
% Method #1: Load into a cell array.
caA{counter} = [1+x,1;2,5];
% Method #2: Load into a 3D regular, normal array
A3D = cat(3, A3D, [1+x,1;2,5]);
counter = counter + 1;
end
% Print to command window
celldisp(caA)
A3D
Finally I refer you to the FAQ http://matlab.wikia.com/wiki/FAQ#How_can_I_create_variables_A1.2C_A2.2C....2CA10_in_a_loop.3F

更多回答（1 个）

sst
sst 2014-5-30
编辑：sst 2014-5-30

0 个投票

This should not require a for loop:
x = [-20:-1, 1:20].';
Amatrices = arrayfun(@(X) [1+X, 1; 2, 5], x, 'UniformOutput', false);

类别

在 帮助中心 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by