trouble with complicated loop

2014 6 10
1 个回答
回答已采纳
更新时间：2014 6 10
1 次查看（30 天）

0 个投票

Hello guys would u please help me in this question Let’s say the length of x=1000, I want to make a loop to calculate the value of A For I=1:x A=(1/I)*(x+1) %when the value of x=1 % when the value of x=2 the formula should be A=(1/I)*(x+2) + ((1/I-1)*(x+1)) % when the value of x=2 the formula should be A=((1/I)*(x+3)) + ((1/I-1)*(x+2) +(1/I-3)* (x+1))
. . . . and so on my question is how can I make this loop in a right way in order to calculate the value of A starting from x=1 till x=1000 thanks in advance

2 个评论
显示 无 隐藏 无

Roger Wohlwend
Roger Wohlwend 2014-6-10
It seems that there are some typos in the formulas. Please make sure that the equations are correct - especially the one for x = 2;
Rock Rocky
Rock Rocky 2014-6-10
Ok let me put it in this way, I want to make a loop in order to add the current state with the previous state for example. M=1000; for i=1:M A=i*(x(i)); % this formula will be for M=1 but when M=2 the formula will be like this A=(i*(x(i))+((i-1)*(x(i-1)))and when M=3 the formula will be A=(i*(x(i))+((i-1)*(x(i-1)))+((i-2)*(x(i-2)) and so on till reach the maximum length of M which is 1000.

请先登录，再进行评论。

请先登录，再回答此问题。

 采纳的回答

David Sanchez
David Sanchez 2014-6-10

0 个投票

% You are playing with two differet indeces: _i_ and _M_.
% You have to fix _i_ and then perform the summation:
x=rand(10,1); % sample data
M=4; % choose your own M
i = M + 1; % i has to be greater than M. Otherwise an error will occur.
A = 0; % initialize the summation
for k=1:M
A= A + (i-(k-1))*x(i-(k-1));
end

1 个评论
显示 -1更早的评论 隐藏 -1更早的评论

Rock Rocky
Rock Rocky 2014-6-10
Much thanks Mr David Sanchez I really appreciate your answer my best wishes to you.

请先登录，再进行评论。

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by