Multiple 2-D area plots in a 3-D graph

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riccardo
riccardo 2014-6-14
评论： Ziao ZHANG 2021-4-21
Hi everyone! I need to plot several 2-D (positive)curves orthogonal to the "x,y plane" in a 3-D plot and I would need to fill the area beneath each 2-D curve. In other words, each filled 2-D graph should lie in an plane orthogonal to "x,y" and the projection of each filled graph should be a different line in the "x,y" plane (not necessarily parallel to each other). Does it exist a matlab function for this sort of task?
I already tried with "fill3". It plots the orthogonal 2-D filled curves but I don't know how to set the curve in the z-axis to an arbitrary function instead of just a straight line.
figure
X = [0 0;1 -0.5;1 -0.5];
Y = [0 0;1 -0.3;1 -0.3];
Z = [0 0;0 0;0.5 0.5];
C = [1.0000;
1.0000;
1.0000];
fill3(X,Y,Z,C)
Can anybody help me?

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回答（3 个）

Star Strider
Star Strider 2014-6-14
You may want to experiment with the area plot:
x = linspace(0,10);
figure(1)
area(x, sin(0.5*pi*x).^2, 'FaceColor',[0 0 1])
hold on
area(x, 2+10*exp(-((x+5).^2)*10)+sin(7*pi*x)*1, 'BaseValue', 2, 'FaceColor',[1 0 0])
area(x, 4+10*exp(-((x+5).^2)*10)+sin(sin(0.5*pi*x)*3*pi)*1, 'BaseValue', 4, 'FaceColor',[0 1 0])
hold off
  2 个评论
Image Analyst
Image Analyst 2014-6-14
riccardo's "Answer" moved here:
Thanks for the suggestion. I have already tried with "area" plot but all the "area" plots lay in the "x,y" plane. Is there a way to rotate them in a 3-D plot and set them to an arbitrary location in the space? (Not necessarily all parallel to each other)
Star Strider
Star Strider 2014-6-14
I can’t run your code because ‘Polyhedron’ is not defined.
See if the File Exchange (FES) contribution Line Plot 3D will do what you want. I don’t know if it produces the filled areas below the line, but it otherwise may do what you want.
The only other option I can suggest is the bar3 function.

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krishna teja
krishna teja 2020-4-14
use watefall command
it does exactly same as what you want
Nactions = 5;
Ntime = 5;
x = (1:Nactions); % actions
y = (1:Ntime); % time
[X,Y] = meshgrid(x,y);
z = rand(Ntime,Nactions);
w = waterfall(X,Y,z)
w.EdgeColor = 'b';
w.EdgeAlpha = 0.5;
w.FaceColor = 'b';
w.FaceAlpha = 0.2;
xlabel('actions')
ylabel('time')
zlabel('probabilities')
title('waterfall')
riccardo
riccardo 2014-6-14
编辑：Star Strider 2014-6-14
Another test I made is the following. What I would need in this case is to fill the area beneath each curve. Any suggestion??
ExtremePoints = [ 1.3 -5.8; -6.2 -3.4; +4.2 5.2; -5.8 -7.7];
P5 = Polyhedron([ 1.3 -5.8; -6.2 -3.4; +4.2 5.2; -5.8 -7.7]);
P5.plot('color', 'lightblue');
hold on;
plot3(x_1, -0.7*x_1, y_1(x_1));
plot3(x_1, x_1, y_1(x_1));
axis auto;
zlim([0, 100])
  1 个评论
Star Strider
Star Strider 2014-6-14
I can’t run your code because ‘Polyhedron’ is not defined.
See if the File Exchange (FES) contribution Line Plot 3D will do what you want. I don’t know if it produces the filled areas below the line, but it otherwise may do what you want.
The only other option I can suggest is the bar3 function.

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