1 个投票

Hi, I have the following code:
for m=1:10
for n=1:sz(2)
if(Isingle(m,n)==1)
index1=[m n];
break;
end
end
end
I need to exit from the entire for loop i.e. for m=1:10 and for n=1:sz(2) when any index value is found, i don't know how to do that. can any body help?
Thanks

请先登录，再回答此问题。

 采纳的回答

Andrei Bobrov
Andrei Bobrov 2011-8-10

0 个投票

[i1 j1] = find(Isingle' == 1, 1, 'first')
OR with loops
for m=1:10
for n=1:sz(2)
if(Isingle(m,n)==1)
index1=[m n];
return
end
end
end

更多回答（1 个）

Friedrich
Friedrich 2011-8-10

4 个投票

Hi,
I think you have to use a flag
flag = 0
for m=1:10
for n=1:sz(2)
if(Isingle(m,n)==1)
index1=[m n];
flag = 1
break;
end
end
if flag == 1
break;
end
end

2 个评论
显示 无 隐藏 无

Friedrich
Friedrich 2011-8-10
Thanks, your are right. fixed it.
Tong Zhao
Tong Zhao 2022-6-26
Thanks from 2022, very educational.

请先登录，再进行评论。

类别

在 帮助中心 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by